Here is the loop from the video, kept as one card. An ammeter sits before the bulb, and a second ammeter sits after it.
A glowing bulb takes energy from the charge passing through it. The charge itself flows on, with nothing missing.
The bulb is not special. The same ledger balances at the resistor, at the wires, and at every other point on the loop. Even the battery adds no charge: it gives the passing charge energy.
One wrong picture is worth naming: a component never uses up part of the current. Whatever charge a component receives each second, it hands on in full. Only the charge's energy is left behind.
In one second, 0.4 C of charge flows into a motor in a series loop. How much charge flows out of the motor in that second?
Write down the fact:
Charge cannot be created, destroyed, or used up, and a series loop has no junctions.
Apply it:
All the charge that flows into the motor each second must flow out of it.
0.4 C of charge flows out of the motor in that second.
Each second, 1.2 C of charge flows out of a heater in a series loop. How much charge flowed into the heater in that second?
Write down the fact:
Charge cannot be created, destroyed, or used up, and a series loop has no junctions.
Apply it, running the ledger backward:
All the charge that flows out of the heater each second must have flowed into it.
1.2 C of charge flowed into the heater in that second.
In a series loop, the current after a heater equals the current before it. Why?
Rosa says a bulb in a series circuit uses up some of the current, so less current flows back to the battery. Is Rosa correct?
In each second, 0.25 C of charge flows into a buzzer in a series loop. How much charge flows out of the buzzer each second?
In a series circuit, an ammeter after a motor reads the same as an ammeter before it. Which statement explains why?
A series loop carries 0.6 A into a resistor, and the resistor gets hot. What is the current out of the resistor?
Which statement is true of the charge flowing around a series circuit?