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Power from force and speed

A tugboat pulls a ship along a canal with a constant 2000 N force, parallel to the motion, at a steady 3 m/s.

No single job's work total is named, and no stopwatch time: just a force and a speed. What power does the tug deliver?

A steady speed of 3 m/s means the ship covers 3 m in each second.

So in each second, the 2000 N force acts through 3 m of distance. 2000 × 3 = 6000. The tug does 6000 J of work each second: 6000 W.

watershiptugboat2000 N3 m each second
Each second, the 2000 N force acts through 3 m.
That move is an equation of its own: P = Fv, for a constant force parallel to the direction of motion.

F is the force in newtons; v is the steady speed in meters per second; P comes out in watts.

One second of towingquantityvalueforce on the ship2000 Ndistance covered each second3 mwork done each second6000 J
Work each second: 2000 × 3 = 6000. That rate is 6000 W.

The same force at a greater speed transfers energy at a greater rate. At a steady 6 m/s, the same force gives 2000 × 6 = 12000, so 12000 W: double the speed, double the power.

Same force, greater steady speedsteady speedpower delivered3 m/s6000 W6 m/s12000 W
Double the speed at the same force: double the power.

Nothing new hides in P = Fv. It is still work per second, with the force acting through the distance the motion covers each second.

A tugboat applies a constant 2000 N force to a ship, parallel to the motion, at a steady 3 m/s. Calculate the power delivered.

Write down the values in the question:

F = 2000 N, v = 3 m/s; P = ?

Write down the equation:

P = Fv

Substitute in the values, and calculate:

P = 2000 × 3 = 6000

The tug delivers 6000 W.

A tow cable applies a constant 420 N force to a trailer moving at a steady 5 m/s, parallel to the motion. Enter the power delivered, in watts.

A tractor applies the same constant force to a loaded sled while its steady speed rises. Edda says: 'The tractor now transfers energy at a greater rate.' Is she correct?

A cable applies a constant 350 N force to a mine cart moving at a steady 8 m/s, parallel to the motion. Calculate the power delivered.

Write down the values in the question:

F = 350 N, v = 8 m/s; P = ?

Write down the equation:

P = Fv

Substitute in the values, and calculate:

P = 350 × 8 = 2800

The cable delivers 2800 W.

A truck's driving force stays a constant 900 N while its steady speed doubles from 4 m/s to 8 m/s. Enter the new power delivered, in watts.

Your turn

A snow groomer's winch cable applies a constant 650 N force to a sled of equipment moving at a steady 12 m/s, parallel to the motion. Enter the power delivered, in watts.

For which situation does P = Fv give the power delivered by the force?

An electric van's motor applies a constant 540 N driving force at a steady 15 m/s on a level road. Enter the power delivered, in watts.