← Kinematic equations

Rearranging Δx = v₀t + ½at² for the acceleration

A runner moving at 5 m/s accelerates at a constant 2 m/s² for 4 s. Calculate the runner's displacement, in m.

Here is a go-kart crossing a line at 3 m/s.

It covers the next 40 m in 4 s. What acceleration did that take? The unknown is a — and in Δx = v₀t + ½at², the a sits inside the second term.

Three moves free a: take v₀t from both sides, multiply both sides by 2, then divide both sides by t².

Δx = v₀t + ½at²Δx − v₀t = ½at²2(Δx − v₀t) = at²a = 2(Δx − v₀t) / t²

Now solve the go-kart question with the same steps as always.

1. Write down the values in the question, and mark the unknown.

quantityvaluea?← find thisΔx40 mv₀3 m/st4 s
2. Write down the equation.Δx = v₀t + ½at²3. Make a the subject.a = 2(Δx − v₀t) / t²4. Substitute in the values, and simplify.a = 2(40 − (3)(4)) / 4²a = 2(40 − 12) / 16a = 56 / 16a = 3.5 m/s²

A car moving at 4 m/s covers 60 m in 5 s while its acceleration stays constant. What is that acceleration, in m/s²? Enter the number only.

A rowing shell gliding at 9 m/s covers only 24 m in the next 4 s while its acceleration stays constant. What is that acceleration?

Write down the values in the question:

Δx = 24 m

v₀ = 9 m/s

t = 4 s

Write down the equation:

Δx = v₀t + ½at²

Make a the subject:

a = 2(Δx − v₀t) / t²

Compute the v₀t term:

v₀t = 9 × 4 = 36 m

Substitute in the values, and calculate:

a = 2 × (24 − 36) / 4²

a = 2 × (−12) / 16

a = −1.5 m/s²

The shell covered less than the 36 m its starting velocity alone would have covered, so it was slowing.

A motorcycle moving at 6 m/s covers 36 m in 3 s while its acceleration stays constant. What is that acceleration, in m/s²? Enter the number only.

A truck moving at 12 m/s covers 50 m in 5 s while its acceleration stays constant. What is that acceleration, in m/s²? Include the sign in your answer.

Back to the go-kart: it crossed the line at 3 m/s and covered 40 m in 4 s. We now know its acceleration was 3.5 m/s² — worked out from nothing but a stopwatch and the length of the track.

Your turn

A car moving at 6 m/s covers 60 m in 4 s while its acceleration stays constant. What is that acceleration, in m/s²? Enter the number only.

A van moving at 8 m/s covers 70 m in 5 s while its acceleration stays constant. What is that acceleration, in m/s²? Enter the number only.

A tractor moving at 10 m/s covers 42 m in 6 s while its acceleration stays constant. What is that acceleration, in m/s²? Include the sign in your answer.