← Motion graphs 2: velocity-time

Find the flaw in an offered velocity-time graph

A student walks 4 m in the positive direction in 4 s, stands still for 2 s, then walks 4 m farther in the positive direction in 4 s. The graph shown is offered for the walk. What is the flaw?

time t (s)position x (m)0123456789100+1+2+3+4+5+6+7+8

A boat crosses to an island dock: it holds a steady 4 m/s for 3 s, then sits at rest at the dock for the next 3 s. A classmate offers this drawing of the trip.

time t (s)velocity v (m/s)36+4

The drawing says something the boat never did. What does it claim?

Judge an offered velocity-time graph exactly as you judged offered position-time graphs: check the description against the graph, one stage at a time.

Stage 1 says a steady 4 m/s for 3 s. The offered first segment sits flat at 4 m/s until t = 3 s. That stage matches.

Stage 2 says at rest. At rest is v = 0 m/s: a segment lying ON the time axis. The offered stage 2 is a ramp from 4 m/s down to zero, above the axis almost to the end. The ramp claims the boat spends all 3 s still moving, only reaching rest at t = 6 s. That is the flaw.

time t (s)velocity v (m/s)36+4at rest: on the axis
The corrected graph: the stop itself is quick, a steep narrow drop at t = 3 s, and the at-rest stage lies on the axis for its full 3 s.
To report a flaw, name the segment and the claim it breaks. The side of the axis must match the direction, at rest lies on the axis, and a change the description gives a duration cannot be drawn as a vertical jump.

A runner runs at a steady velocity in the positive direction for 6 s. The graph shown is offered for the run. What is the flaw?

time t (s)velocity v (m/s)01234560+1+2+3+4+5+6+7+8

The description says the velocity is steady, so the graph should be one flat segment at that velocity.

The offered line rises from 0 to 6 m/s. On a velocity-time graph, a rising line claims the runner speeds up from rest.

This rising line is the position-time shape for a steady run, drawn on the wrong graph.

The flaw is the rising segment: it claims steady speeding up, and a steady velocity needs a flat segment at its level.

A taxi holds a steady 6 m/s for 2 s, then is at rest for 4 s. The graph shown is offered for this trip. What is the flaw?

time t (s)velocity v (m/s)01234560+1+2+3+4+5+6+7+8

A drone flies at a steady 4 m/s in the positive direction for 5 s. The graph shown is offered for the flight. What is the flaw?

time t (s)velocity v (m/s)0123450+1+2+3+4+5+6+7+8+9+10+11+12

A kayak cruises at a steady 5 m/s in the negative direction for 4 s. The graph shown is offered for the cruise. What is the flaw?

time t (s)velocity v (m/s)01234−8−7−6−5−4−3−2−10+1+2+3+4+5+6+7+8

The flat shape is right: a steady velocity is a flat segment.

But the segment sits above the time axis, claiming motion in the positive direction.

Negative-direction motion sits below the axis: the correct segment is flat at −5 m/s.

The flaw is the side of the axis: the kayak's segment must lie at −5 m/s, below the time axis.

A swimmer swims at a steady 3 m/s in the negative direction for 6 s. The graph shown is offered for the swim. What is the flaw?

time t (s)velocity v (m/s)0123456−5−4−3−2−10+1+2+3+4+5

Your turn

A tractor brakes steadily from 9 m/s to rest over 3 s, then stays at rest for 3 s. The graph shown is offered for this stop. What is the flaw?

time t (s)velocity v (m/s)01234560+1+2+3+4+5+6+7+8+9+10

A cart slows steadily from 8 m/s, reverses direction at t = 4 s, and reaches -4 m/s at t = 6 s. The graph shown is offered for this motion. What is the flaw?

time t (s)velocity v (m/s)0123456−6−5−4−3−2−10+1+2+3+4+5+6+7+8+9+10

A car accelerates steadily from rest for 3 s, then holds its top speed for 3 s. The graph shown is offered for this trip. What is the flaw?

time t (s)velocity v (m/s)01234560+1+2+3+4+5+6+7+8